=INDEX(C3:N22,MATCH(G26,B3:B22),MATCH(H26,C2:N2))
Exactly!
--
HTH
Bob Phillips
(replace somewhere in email address with gmail if mailing direct)
"Dave F" wrote in message
...
I just created this formula, and it works correctly, however I'm trying to
understand WHY it works.
As I understand it, INDEX can be used to find the value of an intersection
of a row and column in an array? =MATCH(G26,B3:B22) = 8 and
=MATCH(H26,C2:N2) = 9
So the INDEX function returns the value at the intersection of the eighth
row and ninth column in the above array.
Is this correct?
Dave
--
Brevity is the soul of wit.
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