Posted to microsoft.public.excel.misc
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need sumproduct
[$ 1.233 ] [ 33.22 ]
[$ 0.245 ] [ 11.21 ]
[$ 0.122 ] [ -3.215 ]
Format column C as NUMBER set to 15 decimal places:
=A1*B1
=A2*B2
=A3*B3
=SUM(C1:C3)
Result = 43.314480000000000
=ROUND(SUMPRODUCT(A1:A3,B1:B3),2)
Result = 43.31
Biff
"T. Valko" wrote in message
...
See this:
http://cpearson.com/excel/rounding.htm
Biff
"driller2" wrote in message
...
Still unknown, thanks for your suggestion T.Valko,
From below new sample (e.g) i had tried the three(3) suggested
formula.
[col A] [col B] [rounded product A*B]
[$ 1.233 ] [ 33.22 ] [ $ 40.96 ]
[$ 0.245 ] [ 11.21 ] [ $ 2.75 ]
[$ 0.122 ] [ -3.215 ] [ $ -0.39 ]
from the above sample the sum of the product (2 decimals) = $43.32 (in
thousands...)
=ROUND(SUMPRODUCT(A1:A3,B1:B3),2) result is [$43.31 < $43.32]
=SUMPRODUCT(ROUND(A1:A3,2),ROUND(B1:B3,2)) result is [$43.2767 <
$43.32]
=ROUND(SUMPRODUCT(ROUND(A1:A3,2),ROUND(B1:B3,2)),2 ) result is [$43.28
< $43.32]
___
since last week, this is still a mystery for me where to find a single
formula to do this job, perfectly.
I do tried Roundup and Roundown, even, but the perfect result varies as
the data changes
___
Hope anyone else can give a single sumproduct formula or other evolved
formula.
happy holidays hohoho...:)
romelsb 4pinoy :) on banter
T. Valko Wrote:
It depends on what you actually want. Try these based on your example
and
note the difference:
=ROUND(SUMPRODUCT(A1:A3,B1:B3),2)
=SUMPRODUCT(ROUND(A1:A3,2),ROUND(B1:B3,2))
=ROUND(SUMPRODUCT(ROUND(A1:A3,2),ROUND(B1:B3,2)),2 )
The first formula returns the result you posted.
Biff
--
driller2
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