This will give you the position of the last colon in C6

=LOOKUP(2^15,FIND(":",C6,ROW(INDIRECT("1:"&LEN(C6) ))))

therefore to get the 7 digits following:

=MID(C6,LOOKUP(2^15,FIND(":",C6,ROW(INDIRECT("1:"& LEN(C6)))))+1,7)

neither needs to be "array entered"

"JMB" wrote:

Just change the cell references from A1 to C6.

"KonaAl" wrote:

Thanks for the reply, JMB. Assuming the "1:" s/b ":1", I couldn't get this
to work. I tried changing the A1 references to C6, for example, and still
got a #REF! error. Both times I entered as an array.

Even after looking at the help files for ROW and INDIRECT, I can't figure
this out. Your help is appreciated.

Allan

"JMB" wrote:

One way

=MAX((MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)=":")*( ROW(INDIRECT("1:"&LEN(A1)))))

entered using Cntrl+Shift+Enter or you will get 0 or 1.


"KonaAl" wrote:

Hi All,

I need to be able to return an account number (7 digits) from a text string.
The account number is preceded by a colon. I'm very familiar with find,
left, len, right functions, etc. My problem is the there can be several
colons in the string and the position changes. For example:

Text 1
1000000 · Cash & Cash Equivalents:1010000 · Cash Accounts:1012000 ·
IBT:1012600 · IBT Cash {WF}

Text 2
1000000 · Cash & Cash Equivalents:1010000 · Cash Accounts:1013000 · IBT - B
of A

What I need is 1012600 from the first string and 1013000 from the second.

I can't figure out how to obtain the position of the last colon in the string.

TIA,

Allan