Average if
You have *uneven* range sizes!
You could try this *non-array* formula if you *don't* have negative values:
=SUM(B9:B17,B24:B55)/(COUNTIF(B9:B17,"0")+COUNTIF(B24:B55,"0"))
If you *do* have negatives, try this *non-array* formula :
=SUM(B9:B17,B24:B55)/SUM(COUNTIF(B9:B17,{"0","<0"})+COUNTIF(B24:B55,{" 0","
<0"}))
--
HTH,
RD
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"Curtis" wrote in message
...
Thanks
But when I use the formula
{=AVERAGE(IF(CHOOSE({1,2},B9:B17,B24:B55)<0,CHOOS E({1,2},B9:B17,B24:B55)))}
it returns a value of #N/A
What am I doing wrong?
"Biff" wrote:
Hi!
Is this what you mean?
Average A1:A5 and F1:F5?
If so, try this:
Entered as an array using the key combination of CTRL,SHIFT,ENTER (not
just
ENTER):
=AVERAGE(IF(CHOOSE({1,2},A1:A5,F1:F5)<0,CHOOSE({1 ,2},A1:A5,F1:F5)))
Biff
"Curtis" wrote in message
...
How do I calculate the averages of numbers in 2 sets of ranges...
excluding
zero vaules?
Thanks
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