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Sam via OfficeKB.com Sam via OfficeKB.com is offline
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Default Return Numeric Values Matching EXACT Date for Criteria

Hi Domenic,

Thanks for reply and your assistance. Cell AB4 does just contain a one or
two digit number.

So, I'm using your second suggestion:
($AB$4&"/"&TEXT($B22,"mmm/yy"))+0


What does the +0 actually do?

Cell AB4 contains the two digit number 31 and the month in B22 is June. It
returns has #N/A. Should it have returned #VALUE as the 31 June does not
exist?

=INDEX(OFFSET(Data,0,0,,10),MATCH($AB$4&"/"&TEXT($B22,"mm/yy")+0,Date,0),
COLUMN(A:A))

Cheers,
Sam

Domenic wrote:
Does AB4 contain a true date value formatted to display the day, or does
it actually contain a one or two digit number. If the former, try
replacing...


DATE(YEAR($B22),MONTH($B22),DAY($AB$4))


with


(TEXT($AB$4,"d")&"/"&TEXT($B22,"mmm/yy"))+0


Otherwise, try...


($AB$4&"/"&TEXT($B22,"mmm/yy"))+0


Note that the formula will return #VALUE! when the date doesn't exist,
such as 31/06/2006, and will return #N/A when the date is not found. If
so desired, the formula can be amended to trap error values.


Hope this helps!


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