BTW, if you're really wedded to the use of IF functions, there is a sort of
workaround for the limit of 7 nested functions:
http://www.cpearson.com/excel/nested.htm

Dave
--
Brevity is the soul of wit.


"Dave F" wrote:

Well, there are two problems:

1) You are limited to 7 nested IF functions
2) You have too few closing parentheses.

Since you violate number 1 above, number 2 is irrelevant. I would create a
lookup table with the values for which you want to test the value of C and
then us a VLOOKUP function to return the appropriate number.

Dave
--
Brevity is the soul of wit.


"kris" wrote:

I am trying to put thge following formula into one cell (C5) and the formula
error keeps popping. Does anyone have any suggetions how to enter this
formula correctly into one cell?


IF(C5<=0.49,"6",IF(C5<=0.99,"5.75",IF(C5<=1.49,"5. 5",IF(C5<=1.99,"5",IF(C5<=2.49,"4.75",IF(C5<=2.99, "4.75",IF(C5<=3.99,"4.5",IF(C5<=4.99,"4.375",IF(C5 <=5.99,"4.25",IF(C5<=6.99,"4.125",IF(C5<=7.99,"4", IF(C5<=8.99,"3.75",IF(C5<=9.99,"3.625",IF(C5<=19.9 9,"3.5",IF(C5<=29.99,"3.375",IF(C5<=39.99,"3.25",I F(C5<=49.99,"3.125",IF(C5<=59.99,"3",IF(C5<=69.99, "2.75",IF(C5<=79.99,"2.625",IF(C5<=89.99,"2.5",IF( C5<=99.99,"2.3332",IF(C5<=139.99,"2.2499",IF(C5<=1 69.99,"2.1666",IF(C5<=199.99,"2",IF(C5<=239.99,"1. 855",IF(C5<=269.99,"1.8225",IF(C5<=299.99,"1.7862" ,IF(C5<=349.99,"1.75",IF(C5=399.99,"1.725",IF(C5<= 499.99,"1.6875",IF(C5<=749.99,"1.6",IF(C5<=999.99, "1.55",IF(C5<=1499.99,"1.5",IF(C5<=1999.99,"1.45", IF(C5<=2999.99,"1.4",IF(C5<=4999.99,"1.35",IF(C5<= 9999.99,"1.3375",IF(C5<=24999.99,"1.3333",IF(C5<=4 9999.00,"1.33"))