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Dana DeLouis Dana DeLouis is offline
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Default Activating Function

Hi. Hmmm. Help in Excel 2003 doesn't actually say that it returns
Integers.
If you do the following, and copy down, you will see that it only returns
Integer values.

=RANDBETWEEN(1,100)

Maybe something like:
=0.9+RAND()*0.2

--
HTH :)
Dana DeLouis
Windows XP & Office 2003


"Nat" wrote in message
...
I just used the Add-In tool to activate additional spreadsheet function. I
now have a function in place [=RANDBETWEEN(0.9,1.1)] but it isn't active,
i.e. the cell displays the number "1" and when I use the cell as a
multiplier
it multiplies by one. In other words, the cell isn't functioning by giving
me
random numbers between 0.9 and 1.1.

I suspect that there is some sort of "activation" key combination that I
have to hit to get the function to operate - but I don't know what it is.