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vlookup returns #N/A if value contains letters and range numbers
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paul
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vlookup returns #N/A if value contains letters and range numbe
and the two values dont match.
1028600680B vs 1102900068
--
paul
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"Dave Peterson" wrote:
my guess...
The value in C2 is a real number--if you used:
=isnumber(c2)
in an empty cell, what gets returned?
I'm guessing True.
And =left() returns a string--and excel treats a string that looks like a number
differently from a that real number.
'123 < 123
(text 123 < number 123)
====
You have a couple of solutions. One is to convert all those values in column C
to text.
You can use a helper column (D??) and do something like:
=c1&""
and drag down.
Then select column D
edit|copy
select column C
edit|Paste special|Values
and delete column D (we're done with it).
Then format the "new" column C as Text so that any new entries/changes to
existing entries will be Text.
====
Another way is to use a different formula:
This array formula works ok for me:
=VLOOKUP(LEFT(B2,10)&"*",""&C1:C100,1,0)
This is an array formula. Hit ctrl-shift-enter instead of enter. If you do it
correctly, excel will wrap curly brackets {} around your formula. (don't type
them yourself.)
Adjust the range to match--but you can't use the whole column.
====
Since you're actually returning the first column in the lookup range, =vlookup()
seems like an unusual choice. I think I'd use this array formula:
=INDEX(C1:C100,MATCH(LEFT(B2,10)&"*",""&C1:C100,0) )
(still array entered)
====
One of the differences between these two alternative formulas is what is
returned. In the first (=vlookup()), a text value is returned.
In the second formula (=index(match()), whatever is in column C will be
returned--text or number.
checkQ wrote:
A B C
040W02193A 040W02193A0B 040W02193A
#N/A 1 1028600680B 1102900068
Formula used in column A is=VLOOKUP(LEFT(B1,10)&"*",C:D,1,0)
The value that I am looking for is in the first 10 characters in column B
that match the first 10 characters in column C
The formula works for the first line but returns an #N/A for the second
line
I believe it is because my column B has the letter B in it and column C does
not have any alphabet. Does anyone know a formula to fix this?.
--
Dave Peterson
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