Biff:
Thank you so much for your thorough reply. Once again I'm humbled by the
knowledge within these Discussion Groups. May I confirm two things:

1) The non-array syntax of an IF statement is (per Microsoft Help):
IF(logical_test,value_if_true,value_if_false). Are you saying that the
syntax of an IF
statement within an array is: IF(logical_test,use_only_true_values)? In
other words, the IF statement within an array doesn't result in one value if
it is true and another value if it is false, but rather determines whether
each value within the function may continue to the next argument or not? If
that's the case, then I've had a huge breakthrough in understanding your
formula / arrays.

2) Are you saying True always = 1 and False always = 0? (If so, I probably
should have known that but didn't.)

Once again, THANK YOU SO MUCH.
Elizabeth

"Biff" wrote:
=MIN(IF(MOD(COLUMN(A1:O1),2),IF(A1:O10,A1:O1)) )

The columns are numbered from 1 to 256. Column A = 1, column B = 2, column C
= 3, etc.

Using the MOD function with a divisor of 2, all odd numbered columns will
return a mod of 1 and all the even numbered columns will return a mod of 0.
When these mod results are evaluated by the IF function the mods of 1 are
evaluated as TRUE and the mods of 0 are evaluated as FALSE.

So, this expression will return an array of 1's and 0's:

IF(MOD(COLUMN(A1:O1),2)

This expression which is testing the values in the range to be greater than
0 will return an array of TRUEs and FALSEs:

IF(A1:O10

Where both arrays evaluate to TRUE the corresponding value from the range
array, A1:O1, is passed to the MIN function.

Here's what it would look like using a smaller sample:

A1.....B1.....C1.....D1.....E1
65.....53.....-10.....55......4

IF(MOD(COLUMN(A1),2) = 1
IF(MOD(COLUMN(B1),2) = 0
IF(MOD(COLUMN(C1),2) = 1
IF(MOD(COLUMN(D1),2) = 0
IF(MOD(COLUMN(E1),2) = 1

IF(A10 = TRUE
IF(B10 = TRUE
IF(C10 = FALSE
IF(D10 = TRUE
IF(E10 = TRUE

IF(1,IF(TRUE = A1 = 65
IF(0,IF(TRUE = B1 = FALSE
IF(1,IF(FALSE = C1 = FALSE
IF(0,IF(TRUE = D1 = FALSE
IF(1,IF(TRUE = E1 = 4

=MIN({65,FALSE,FALSE,FALSE,4}) = 4

Biff

"Elizabeth" wrote in message
...
Biff:
I've been puzzling over your suggestion for days. It works, but I don't
understand it. Would you mind telling me what it is doing? I am fairly
new
to arrays. I would appreciate your help. Thank you!
Elizabeth

"Biff" wrote:

Hi!

Try this:

Entered as an array using the key combo of CTRL,SHIFT,ENTER:

=MIN(IF(MOD(COLUMN(A1:O1),2),IF(A1:O10,A1:O1)))

Biff

"MichaelC" wrote in message
...
I have an array that is 1 row high by 16 columns wide.
Each cell may contain a positive value, or a zero.

I need a formula to find the "Minimum value that is greater than zero"
in
columns 1,3,5,7,9,11,13 and 15.

=MIN(A1,C1,E1,G1,I1,K1,M1,O1) will always return the zero value while I
need the minimum value that is greater than zero.
If I use nested IF functions to exclude zeroes I run foul of the max of
7
allowed.
I would greatly appreciate any help and thank you in advance for any
offered.
MichaelC