Thanks for the correction/enhancement.

JE McGimpsey wrote:

Note that that formula will count blanks as "<0", so will underestimate
the average if there are blanks in the range.

One array-entered (CTRL-SHIFT-ENTER or CMD-RETURN) workaround, if blanks
are a problem:

=SUM(BJ3:BJ32)/SUMPRODUCT(--(BJ3:BJ32<0),--ISNUMBER(BJ3:BJ32))

which results in 0, not "" if there are no non-zero numbers in the range.

If you want "" instead, one way:

=IF(SUMPRODUCT(--ISNUMBER(BJ3:BJ32),--(BJ3:BJ32<0)), SUM(BJ3:BJ32) /
SUMPRODUCT(--ISNUMBER(BJ3:BJ32),--(BJ3:BJ32<0)), "")

In article ,
Dave Peterson wrote:

You could just check first:

=if(countif(bj3:bj32,"<0")=0,"",SUMIF(BJ3:BJ32,"< 0")/COUNTIF(BJ3:BJ32,"<0")
)



Randy Lefferts wrote:

=SUMIF(BJ3:BJ32,"<0")/COUNTIF(BJ3:BJ32,"<0")

I read a similar post where they needed to suppress the
error message above and the answer was to use =IF(COUNT
(B35:B47)0,AVERAGE(B35:B47,"") to eliminate the error.
Of course, this was in response to the specific formula
the person was using.

So I thought that I could use =IF(COUNT(B35:B47)0,
(insert my functions here),"") and that would work. It
doesn't appear to.

The spreadsheet has each month of the year, broken out by
days. When the current month is September, there is not
information in Oct, Nov and Dec. How to keep the #DIV/0!
error from appearing in those months using =SUMIF
(BJ3:BJ32,"<0")/COUNTIF(BJ3:BJ32,"<0") ?

Thank you !

--

Dave Peterson