Simon,

the problem is that a percentage is a number, it is just shown as a
percentage. Any other characteristics that differentiate, e.g. the 'numbers'
are always greater than 1 but the percentage is always < 100%?

--

HTH

RP
(remove nothere from the email address if mailing direct)


"Simon" wrote in message
...
How do I get an IF function to return a percentage when applicable?

--------------------------------------------------------------------------
------

Here is the problem:

I am using a Concatenated Lookup function in conjunction with a drop down
box. There are three options in the drop down - two are numbers, one is a
percentage.

I need to get the lookup funtion combined with an IF function to say when
I
choose one of the two number options return a number, when I choose the
percentage option, return a percentage.

Any ideas? I looked for a PERCENT funtion but there isn't one!

This one has me stumped.

Thanks

Simon