I guess that your problem may be that
=left(B7,3) will return a text string, whereas your OR formula is looking
for the number 101.

I think you'll find that it will work if you use =VALUE(LEFT(B7,3))

David Biddulph

"Inbar" wrote in message
...
=left(B7,3)

B8 holds this condition in order to cut the left 3 numbers from the value
in
B7.

"Bob Phillips" wrote:

What sort of condition?

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

"Inbar" wrote in message
...
The column B8 does not recognize the value 101 because there is a
condition
on the B8 column. when I remove the condition and simply write the
vlaue
101,
the function works.


=IF(OR(B8=148,B8=149,B8=1501),"Mellon",IF(OR(B8=10 1,B8=102),"Watermelon",IF(
B8=184,"Squash",IF(OR(B8=153,B8=154),"Cucumber",IF (OR(B8=173,B8=174,B8=175),
"Peper",IF(OR(B8=163,B8=164,B8=165,B8=166),"Tomato ","N/A"))))))

any idea what to do?

"Inbar" wrote:

My Mistake:
The cell no was wrong.
So thanks for your help!

Inbar

"Paul Mathews" wrote:

=IF(OR(B18=148,B18=150),"A","B")

"Inbar" wrote:

Hi,

I am trying to use the OR function within an IF condition.
when I use each function seperatly, it works fine. but both
functions
together always return the value of "B" - as false result, even
when
the
requested cell holds one of the true values.

for example:
=IF(B18=OR(148,150),"A","B")