Domenic Wrote:
Try the following formula instead...
=COUNT(1/FREQUENCY(IF((LEFT(N1:N3000;2)="SE")+(LEFT(N1:N300 0;3)="INC");IF
(A1:A3000<"";A1:A3000));IF((LEFT(N1:N3000;2)="SE" )+(LEFT(N1:N3000;3)="IN
C");IF(A1:A3000<"";A1:A3000))))
....confirmed with CONTROL+SHIFT+ENTER.
Hope this helps!
In article ,
ajajmannen
wrote:
Ok one step closer.....It counted 0......I think i know why.....I
would
like to use a wildcard on the SE and INC....As all of the values in
that
column either starts with SE or INC so a value can look like INC96835
or
INC99784....Is there a way to get it to match the value with either
a
wildcard or by stating "starts with"?????
I must say many thanks for all the help.....But It still counts it to 0
and I know that it should be around 700 entries at least.
Please help out.....I don't know what more information to give to be
able to get the correct formula.
--
ajajmannen
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