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Posted to microsoft.public.excel.worksheet.functions
Domenic
 
Posts: n/a
Default Count the number of unique Numbers in a column

Try...

=COUNT(1/FREQUENCY(IF(ISNUMBER(MATCH(N1:N3000,{"SE";"INC"}; 0));IF(A1:A300
0<"";A1:A3000));IF(ISNUMBER(MATCH(N1:N3000;{"SE"; "INC"};0));IF(A1:A3000<
"";A1:A3000))))


....confirmed with CONTROL+SHIFT+ENTER.

Hope this helps!

In article ,
ajajmannen
wrote:

Hi!!

I tried your formula but excel is complaining about the Lookup value in
the first Match formula?

When I look at the help it states that the Value I'm looking for should
be second and the Array second but I don't seem to get it right
anyway......

Please help me here
First of all I probably have a diffrent version of excel I use smicolon
instead of colon.
I tried something like this but now it stops at last parentes after the
first IF statement


=COUNT(1/FREQUENCY(IF(ISNUMBER(MATCH({"SE";"INC"};(N1:N2385 );0;IF(A1:A3000<""
;A1:A3000)))
IT stops here and I don't know why??
;IF(ISNUMBER(MATCH({"SE","INC"};(N1:N2385,);0;IF(A 1:A3000<"";A1:A3000)))

=COUNT(1/FREQUENCY(IF(ISNUMBER(MATCH({"SE";"INC"};(N1:N2385 );0;IF(A1:A3000<""
;A1:A3000)));IF(ISNUMBER(MATCH({"SE","INC"};(N1:N2 385,);0;IF(A1:A3000<"";A1:A
3000)))