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Posted to microsoft.public.excel.worksheet.functions
Bob Phillips
 
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Default Array constant issue

Try this instead

=LOOKUP(2;1/(D1:D65535<"");D1:D65535)

--
HTH

Bob Phillips

(remove nothere from email address if mailing direct)

"Sige" wrote in message
ups.com...
Hi There,

IMO this formula should allow me to define what my last row is in
column D
=MAX(CHOOSE({1,2};IF(ISNUMBER(MATCH(REPT("z";255); D:D));MATCH(REPT("z";255);
D:D);0);MATCH(9,99999999999999E+307;D:D)))
Above formula will find me the last row with a TEXT string!

Though I have to change CHOOSE({1,2} to CHOOSE({1;2} to find the last
row with a NUMERICAL value!

Mind I use ";" as argument separator!

What "separator"do I have to use to let it work like it should?
Or is ther another issue?

This is what the HELP tells me:
· Separate values in different columns with commas (,)
· Separate values in different rows with semicolons (;)


Anyone Please,
Sige