View Single Post
  #2   Report Post  
Posted to microsoft.public.excel.misc
Roger Govier
 
Posts: n/a
Default working with dates

Hi

=DATE(YEAR(TODAY()),MONTH(TODAY()),1) for first of month
=DATE(YEAR(TODAY()),MONTH(TODAY())+1,0) for last of month
works on the 0th day of a month is equal to last day of previous month

so
=TEXT(DATE(YEAR(TODAY()),MONTH(TODAY()),1),"mm/dd/yyyy") &" - " &
TEXT(DATE(YEAR(TODAY()),MONTH(TODAY())+0,0),"mm/dd/yyyy")
--
Regards

Roger Govier


"Hru48" wrote in
message ...

Hey all,

I need a cell to work to return the first and last day of the month it
is in without me having to type anything in. In the format
mm/dd/yyyy -
mm/dd/yyyy

I was thinking I could use date(now) and then use date difference to
figure this out but i'm not too sure on the syntax.

Any help would be great.

Thanks.


--
Hru48
------------------------------------------------------------------------
Hru48's Profile:
http://www.excelforum.com/member.php...o&userid=24895
View this thread:
http://www.excelforum.com/showthread...hreadid=506719