AVERAGE function returns #DIV/0! error
Small update to my previous formula, adds the VALUE() function to convert
numbers stored as text to numerical values, still entered CTRL+SHIFT+ENTER:
=AVERAGE(IF(ISNUMBER(VALUE(A1:A10)),VALUE(A1:A10), ""))
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Regards,
Dave
"David Billigmeier" wrote:
Try this. I assumed your range was A1:A10, change this to fit your data.
Enter this formula by using CTRL+SHIFT+ENTER as it is an array formula:
=AVERAGE(IF(ISNUMBER(A1:A10),A1:A10,""))
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Regards,
Dave
"KhaVu" wrote:
I used AVERAGE function in my spreasheet and received #DIV/0! error from it.
Is there a safe proof way to omit the invalid values out of the average
calculation.
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