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Posted to microsoft.public.excel.misc
Ragdyer
 
Posts: n/a
Default Finding a row based on a random value in a column

Since you mentioned A5, are you looking for the return to come from Column
A?
If so, try this *array* formula:

=INDEX(A1:A7,MATCH(TRUE,B1:B7<0,0))

--
Array formulas must be entered with CSE, <Ctrl <Shift <Enter, instead of
the regular <Enter, which will *automatically* enclose the formula in curly
brackets, which *cannot* be done manually.
--
HTH,

RD

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"bobzebra" wrote in message
oups.com...
First, apologies if this has been answered before but I couldn't find
anything close in the forums:

My problem is I need to find the first row reference if a value in one
of the columns is (unpredictably) less than 0. I have tried a mix of
Index, Match and the Excel lookup wizard but to no avail.

For example, at its simplest I have 2 columns x and y

A B
1 x y
2 1 13
3 2 6
4 3 0
5 4 -1
6 5 -12
7 6 4
etc

how do I locate the first row when the y column goes negative. I know
it is simple if I know beforehand ( in this case it is row cell A5) ,
but if the Y column varies at random, I get stuck. Any help much
appreciated
Bob