Good deal! Thanks for the feedback.

Biff

"Dave" wrote in message
...
Biff,
I finally got it to work. In the cells that had multiple values there were
spaces between the commas and each value.That was causing the formula to
only
return the first value in each cell. I t"tweaked" the formula you wrote to
add a space with the commas in quotes and it worked perfectly.

I appreciate yours and Dave's responses to my question. It certainly saved
a
lot time and was much more efficient.

Thanks again, Dave

--
dmp


"Biff" wrote:

Did you try the formula I suggested?

It will only "work" for exact matches.

Biff

"Dave" wrote in message
...
Dave, Bif,
Thanks for the replies. I am a lot closer than I was. Is there an
addition
to the formula that can give me an exact match? The example that Bif
wrote
below is exactly whats happening with some of my data.
--
dmp


"Dave Peterson" wrote:

Yes it does.

Biff wrote:

Suppose the number in A1 is 1.

Sheet2!An = 11,21,31

=countif(sheet2!a:a,"*"&a1&"*")0 returns TRUE

Biff

"Dave Peterson" wrote in message
...
=countif(sheet2!a:a,"*"&a1&"*")0

Will return True if it's found.

You may want to check for empty cells:
=if(a1="","",countif(sheet2!a:a,"*"&a1&"*")0)

or

=isnumber(match("*"&a1&"*",sheet2!a:a,0))
or
=if(a1="","",isnumber(match("*"&a1&"*",sheet2!a:a, 0)))





Dave wrote:

I am looking to produce a formula that shows if a number is
"found"
or
"not
found".
I have list of over 1000 numbers in one column (1 number per row)
.
I am
trying to identify if those values are present in a range of
numbers
from
another worksheet(also in a single column). My challenge is that
the
range of
numbers that I am looking in has multiple values, separated by
commas in
a
single cell. Looks like it was from an Access data dump. Any help
is
appreciated.
--
dmp

--

Dave Peterson

--

Dave Peterson