Did you try the formula I suggested?

It will only "work" for exact matches.

Biff

"Dave" wrote in message
...
Dave, Bif,
Thanks for the replies. I am a lot closer than I was. Is there an addition
to the formula that can give me an exact match? The example that Bif wrote
below is exactly whats happening with some of my data.
--
dmp


"Dave Peterson" wrote:

Yes it does.

Biff wrote:

Suppose the number in A1 is 1.

Sheet2!An = 11,21,31

=countif(sheet2!a:a,"*"&a1&"*")0 returns TRUE

Biff

"Dave Peterson" wrote in message
...
=countif(sheet2!a:a,"*"&a1&"*")0

Will return True if it's found.

You may want to check for empty cells:
=if(a1="","",countif(sheet2!a:a,"*"&a1&"*")0)

or

=isnumber(match("*"&a1&"*",sheet2!a:a,0))
or
=if(a1="","",isnumber(match("*"&a1&"*",sheet2!a:a, 0)))





Dave wrote:

I am looking to produce a formula that shows if a number is "found"
or
"not
found".
I have list of over 1000 numbers in one column (1 number per row) .
I am
trying to identify if those values are present in a range of numbers
from
another worksheet(also in a single column). My challenge is that the
range of
numbers that I am looking in has multiple values, separated by
commas in
a
single cell. Looks like it was from an Access data dump. Any help is
appreciated.
--
dmp

--

Dave Peterson

--

Dave Peterson