"Jane" wrote in message
...
here is my VBA code:

Lastrow = Range("A65536").End(xlUp).Row
Range("L19", "L820").FormulaR1C1 = "0"

For I = 19 To Lastrow
If Range("L15").Value < 0 Then Range("L" & I).ClearContents
Range("L" & I).FormulaR1C1 = _

"=AND(R2C12=1,RC9=1,R3C12<""n"")*RC[12]+AND(R2C13=2,RC9=2,R3C13<""n"")*RC[12]+AND(R2C14=3,RC9=3,R3C14<""n"")*RC[12]+AND(R2C15=4,RC9=4,R3C15<""n"")*RC[12]+AND(R2C16=5,RC9=5,R3C16<""n"")*RC[12]+AND(R2C17=6,RC9=6,R3C17<""n"")*RC[12]+AND(R2C18=7,RC9=7,R3C18<""n"")*RC[12]+AND(R2C19=8,RC9=8,R3C19<""n"")*RC[12]+AND(R2C20=9,RC9=9,R3C20<""n"")*RC[12]+AND(R2C21=10,RC9=10,R3C21<""n"")*RC[12]"
Range("L19").Select
Exit For
End If
Next I

I get the following error: End If without Block If
What do I need to change?
thank you in advance! jane

You don't need End If as your previous If is
a one-line clause (If ... Then ...).

Bruno