Conditional Functions
On Sat, 12 Nov 2005 20:06:02 -0800, "KidMW14"
wrote:
Sorry, I meant that the equation I made was
=IF(OR(O2=0%,(P2-O2)/O2200%),200%,(P2-O2)/O2)
"KidMW14" wrote:
I have data in 2 columns that I want to work with. In one column (O) is a
percentage that sometimes equals 0. In the other (P) is a percentage that
never equals 0. Now in the third column (Q), I have the function =(P2-O2)/O2,
but sometimes, when O=0%, the function doesn't work. So I changed it to say
=IF((O2=0%),200%,(P2-O2)/O2). I never want the Q column to be more than 200%.
It works for numbers that quotient to more than 200%, but for functions where
O=0%, it says #DIV/0!, where it should just say 200%, as I've instructed it.
What should I do?
The problem is that within your initial OR function, which gets executed every
time, you are dividing by 0, hence the error.
Try something like:
=if(o2=0,200%,min(200%,(p2-o2)/o2))
--ron
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