How to apply OFFSET as the range in a basic 'Copy' process...
So long as you're going to put this into VBA, you'll have to abide by VBA's
syntax.
Bob's reply pretty much lays out what VBA allows and what you need. You'll
have to be responsible for converting your formula into the values you need
for the 2 arguments to the OFFSET property and the 2 arguments to the RESIZE
property
"cdavidson" wrote:
My apologies Bob, but I tried to over simplify my actual situation for the
sake of simply getting the proper coding structure from you. My actual
OFFSET formula is far more complicated (pasted below in case it helps). Is
there a way we can stick with my original format of
Range("(OFFSET(...)").Select ??
Thanks
--------------
Actual OFFSET formula...
=OFFSET($H$12,(COUNTIF((INDIRECT("$H$12:H"&(11+(IN DIRECT("_DATAROWS"))))),"<"&"GASHA")),3,(SUMPRODU CT(--((INDIRECT("$H$12:H"&(11+(INDIRECT("_DATAROWS")))) )="GASHA"),--((INDIRECT("$J$12:J"&(11+(INDIRECT("_DATAROWS")))) )=(OFFSET($H$12,(COUNTIF((INDIRECT("$H$12:H"&(11+( INDIRECT("_DATAROWS"))))),"<"&"GASHA")),2,1,1)))) ),4)
"Bob Phillips" wrote:
Range("H12").Offset(7,6).Resize(3,2).Copy
--
HTH
RP
(remove nothere from the email address if mailing direct)
"cdavidson" wrote in message
...
Simply looking to understand how to properly apply the offset command to
identify a range in VBA coding. The respective portion of my 'improper'
code
is shown below. What should the 'Range("...' line of code be? Thanks!
Sub PivotConcept()
Sheets("Pivots").Select
Range("(OFFSET(R12C8,7,6,3,2)").Select
Selection.Copy
.
.
.
End Sub
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