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Dana DeLouis
 
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Hi. That's a good question because the average of 350° and 10° is due
north, and not the average (180°)
I "Think" that one way is to take the average of the East-West, and
North-South components.
With given Degrees in Column A names "Rng", see if this Array Formula will
work...

=DEGREES(ATAN2(AVERAGE(COS(RADIANS(Rng))),AVERAGE( SIN(RADIANS(Rng)))))

If the answer is negative, then add 360.
(ie if -10, then add 360: - 350°)

HTH :)
--
Dana DeLouis
Win XP & Office 2003


"Rex Morgan" <Rex wrote in message
...
I have a data set of wind directions in degrees, rounded to the nearest 10
degrees. I am attempting to take a average of that data set. Any help
would
be greatly appreciated.