"Peter Rooney" wrote in message
...
Good afternoon, fellow Publishers!

This is probably a real no brainer, but what I'm trying to do is create a
six pointed star using basic shapes. I created an equilateral triangle
(15cm
wide by 12.99cm high - basic trig using sin(60) to work out the height,
copied it and flipped the copy upside down. I then aligned the left edges
of
the two stars...and this is where the problem started. No matter how far
up
or down I move one triangle in relation to the other, it just doesn't LOOK
right.

I need some sort of formula to say "given the height of the triangle, how
many cm down from the y origin of the first triange does the second
triange
have to be?"

Unless of course someone can advise me as to how to get a six pointed star
from some other version of "basic shapes"

One third of the way down from the apex is where the base of the other
triangle should cross.

Or you can build your star from 12 equilateral triangles. You can regard it
as 6 in the central hexagon and one on each face of the hexagon, or 9 small
triangles in each of your two big triangles, the overlap between the two
being the six in the hexagon.
Or you can find the centre of your first triangle, draw a circumscribed
circle, & then slide your second triangle to fit in the same circle.
--
David Biddulph