Placing the MsgBox "No ID found" statement in my code??
Hi Garry, hi Howard,
Am Tue, 06 May 2014 13:13:34 -0400 schrieb GS:
Good catch! Should be...
sMsg = sMsg & Join(Split(Mid(sIdShts, 2), ","), vbLf)
..to remove the leading ","!
if you want all matches be listed you must change:
sIdShts = sIdShts & ",'" & ws.Name & "'!" & rng.Address
Regards
Claus B.
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Vista Ultimate / Windows7
Office 2007 Ultimate / 2010 Professional
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