hello can you help fast ? tonight /
How do I convert a decimal number 23.125 to binary?

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'by Rick Rothstein
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Function DecToBin(ByVal DecimalIn As Variant, Optional NumberOfBits As
Variant) As String
' The DecimalIn argument is limited to 79228162514264337593543950266
' (approximately 96-bits) - large numerical values must be entered
' as a String value to prevent conversion to scientific notation.

DecToBin = "": DecimalIn = CDec(DecimalIn)
Do While DecimalIn < 0
DecToBin = Trim$(Str$(DecimalIn - 2 * Int(DecimalIn / 2))) &
DecToBin
DecimalIn = Int(DecimalIn / 2)
Loop
If Not IsMissing(NumberOfBits) Then
If Len(DecToBin) NumberOfBits Then
DecToBin = "Error - Number too large for bit size"
Else
DecToBin = Right$(String$(NumberOfBits, "0") & DecToBin,
NumberOfBits)
End If
End If
End Function

--
Garry

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