On Sun, 18 Nov 2012 11:30:03 +0000, greenemm wrote:

Hi Ron,

Firstly, thank you for taking the time to look into helping me solve my
'problem'.

Your solution has saved me many hours of tedious and monotonous manual
checking. I am very grateful. Thank you so much.

Kind regards

Michael

Glad to help. Thanks for the feedback. Note that the solution depends critically on the absence of duplicate numbers. If there might be duplicates, a different solution will be required.