I am sorry, let me give more detail.
These are the actual values in a portion of the table; If cell "T1" says
".12" I need it to first recognize the closest value, being between 0.1179 &
0.1217. Second since it is closer to 0.1217 it would return the value ".31".
How can this be accomplished please?

0.00 (0.01) 0.02 0.03
0.0 0.0000 0.0040 0.0080 0.0120
0.1 0.0398 0.0438 0.0478 0.0517
0.2 0.0793 0.0832 0.0871 0.0910
(0.3) 0.1179 (0.1217) 0.1255 0.1293
0.4 0.1554 0.1591 0.1628 0.1664
0.5 0.1915 0.1950 0.1985 0.2019
0.6 0.2257 0.2291 0.2324 0.2357
0.7 0.2580 0.2611 0.2642 0.2673
0.8 0.2881 0.2910 0.2939 0.2967
0.9 0.3159 0.3186 0.3212 0.3238
1.0 0.3413 0.3438 0.3461 0.3485
1.1 0.3643 0.3665 0.3686 0.3708

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Thank you!


"Jacob Skaria" wrote:

Array entered with query value in cell T1

=INDEX(Q:Q,MIN(IF($R$3:$AA$41=T1,ROW($R$3:$AA$41)) ))+
INDEX(2:2,MIN(IF($R$3:$AA$41=T1,COLUMN($R$3:$AA$41 ))))

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Jacob (MVP - Excel)


"Doug" wrote:

The other day, I used this formula to lookup table data based on the row and
column such as:
=INDEX($R$3:$AA$41,MATCH(FLOOR($S$1,0.1),$Q$3:$Q$4 1,1),MATCH(FLOOR($S$1-FLOOR($S$1,0.1),0.01),$R$2:$AA$2,0))

So that If I had the number 2.22, it will return for me .15 from the table
lookup table (made up values)
.00 .01 .02 .03 .04 ... .09
2.0 .31 .32 .33 .34 .35 ... .50
2.1 .21 .35 .51 .51 .25 ... .85
2.2 .53 .52 .15 .52 .51 ... .81
2.3 .89 .58 .23 .45 .15 ... .15

My question now is, based on the above formula, how would I be able to do
the opposite. So if I have the indexed value; say .15, and I want it to
return 2.22?

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Thank you!