I think that the backslash should also be included in both lines. Seems to
be OK without if the current default directory is also the activeworkbook
directory but can one be sure of that.

Sub test()

Dim FileToOpen As String

FileToOpen = Dir(ActiveWorkbook.Path & "\" & "*" & "G016" & "*.xls")

If FileToOpen < "" Then
Workbooks.Open ActiveWorkbook.Path & "\" & FileToOpen
End If

End Sub

--
Regards,

OssieMac


"Rick Rothstein" wrote:

Workbooks.Open FileToOpen

The above line from your code should be this...

Workbooks.Open ActiveWorkbook.Path & FileToOpen

Since the Dir function returns only the file's name (without the path
associated with it).

--
Rick (MVP - Excel)



"Gary Keramidas" wrote in message
...
maybe something like this:

Sub test()
Dim FileToOpen As String

FileToOpen = Dir(ActiveWorkbook.Path & "*" & "G016" & "*.xls")
If FileToOpen < "" Then
Workbooks.Open FileToOpen
End If

End Sub


--


Gary Keramidas
Excel 2003


"shiloh13" <u59050@uwe wrote in message news:a5b747aa8da6d@uwe...
Please Help!!

I have a master file called "All Reports.xls" that opens up various
Reports
files(Ex: ABC_G016_GPUS.xls, BCD_G027_GPUS.xls, JKL_G034_GPUS.xls). The
Report files are in the same network folder as the master file and are
updated frequently. The Report files also have names that constantly
change
when they are updated. The only part of the filename that does not
change
begins with "G" followed by 3 numbers. By reading previous posts, I was
able
to figure out how to open the "G016" Report file with the code below.

Workbooks.Open ActiveWorkbook.Path & "ABC_G016_GPUS.xls"

How do I open the file by only the "G016" part of the filename? I tried
the
code below, but it did not work:

Workbooks.Open ActiveWorkbook.Path & "*" & G016 & "*.xls"

I appreciate your help!!


.