You are getting the compile error because you've named your macro the same
thing as you named the variable. Change one or the other, and it should work.

"kyle" wrote:

Don,

the final row still isn't working, i've uploaded a picture to show you what
i mean

http://i87.photobucket.com/albums/k1...icture3-10.png

"Don Guillett" wrote:


finalrow = celss(rows.count, 1).end(xlup).row
finalrow = cells(rows.count, 1).end(xlup).row

endif
end if


sub delete()
for i = cells(rows.count, 1).end(xlup).row to 2 step-1
if cells(i, 8) = 1 then rows(i).delete
next i
end sub


--
Don Guillett
Microsoft MVP Excel
SalesAid Software

"kyle" wrote in message
...
i've got this code built that will delete a row if there is a one in
column h
but it's not working

sub delete()

finalrow = celss(rows.count, 1).end(xlup).row

for i = finalrow to 2 step -1
if cells(i, 8) = 1 then
cells(i, 1).entirerow.delete
endif
next i
end sub

it doesn't work, what do you think is wrong?

.