okay, I think I've now become the idiot here... more so then just asking for
help.... :-(

"JRH" <jrh wrote in message ...
Okay, let try this one again. Sorry for the formatting issue:

Mean hrs= number of subjects/total hours driving (200/1580) = 7.9
Standard Deviation for hours driving: Needs to equal 1.05 I can get
that
by
taking 12702(power1580,2)/200 which = 220
taking that sum (220) and making another calculation. sqrt(220/200-1)
Those combined net the standard deviation, but there has to be an easier
way.... Any help would be appreciated.

# of sub = subjects
x f xf x2f
Hrsdriving #Sub Tot.hrs
3.5 2 7 24.5
4.5 2 9 40.5
5.5 4 22 121
6.5 22 143 929.5
7.5 64 480 3600
8.5 90 765 6502.5
9.5 14 133 1263.5
10.5 2 21 220.5

56 200 1580 12702




"