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marcus[_3_] marcus[_3_] is offline
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Default searching for a type of string

Hi Roger

This should do what you wish, provided there is one character at the
end of your string as text as you had in your example. If there are
more you may need something else.

=IF(ISNUMBER(VALUE((MID(A1,1,LEN(A1)-1)))),1,0)

Take care

Marcus