On Oct 28, 4:02*pm, "JLGWhiz" wrote:
This is the correct syntax:

If WorksheetFunction.CountA(Sheets("All Other Funds Centers") _
.Columns("E:E")) < 0 And WorksheetFunction. _
CountA(Sheets("All Other Funds Centers").Columns("G:G")) < 0 Then

"dhermus" wrote in message

...
On Oct 28, 11:24 am, "JLGWhiz" wrote:





This is an example of one method:

If Sheets("All Other Funds Centers").CountA(Columns("E:E")) < 0 _
And Sheets("All Other Funds Centers").CountA(Columns("G:G")) _
< 0 Then

Sheets("All Other Funds Centers").Columns("E:E").TextToColumns _
Destination:=Range("E1"),DataType:=xlDelimited, _
TextQualifier:=xlSingleQuote, ConsecutiveDelimiter:=False, _
Tab:=True, Semicolon:=False, Comma:=False, Space:=False, _
Other:=False, FieldInfo:=Array(1, 1), TrailingMinusNumbers:=True
Sheets("All Other Funds Centers").Columns("G:G").TextToColumns _
Destination:=Range("G1"), DataType:=xlDelimited, _
TextQualifier:=xlSingleQuote, ConsecutiveDelimiter:=False, _
Tab:=True, Semicolon:=False, Comma:=False, Space:=False, _
Other:=False, FieldInfo:=Array(1, 1), TrailingMinusNumbers:=True

End If

I took the liberty of eliminating the Select and Selecion from your code
since they are not needed to make the code work. The If statement, using
CountA function, will check to see if there is data in the two columns
before you try to do anything with them. If there is no data it moves on
to
the next block of code. You can do the same thing with the rest of your
code. Since this particular example checks both columns E and G, it could
still throw an error if one column has data but the other does not. To get
around that, you would need to make an If...Then statement for each
column.

"dhermus" wrote in message

....

I am using the following script to format columns in two worksheets
upon opening a workbook. There will not always be data in the selected
columns. My problem is the macro errors when there is no data
present. How can I bypass the errors and complete the macro for the
other columns that do have data?

Sheets("All Other Funds Centers").Select
Columns("E:E").Select
Selection.TextToColumns Destination:=Range("E1"),
DataType:=xlDelimited, _
TextQualifier:=xlSingleQuote, ConsecutiveDelimiter:=False,
Tab:=True, _
Semicolon:=False, Comma:=False, Space:=False, Other:=False,
FieldInfo _
:=Array(1, 1), TrailingMinusNumbers:=True
Columns("G:G").Select
Selection.TextToColumns Destination:=Range("G1"),
DataType:=xlDelimited, _
TextQualifier:=xlSingleQuote, ConsecutiveDelimiter:=False,
Tab:=True, _
Semicolon:=False, Comma:=False, Space:=False, Other:=False,
FieldInfo _
:=Array(1, 1), TrailingMinusNumbers:=True

Range("A57").Select
Sheets("Spec Init - 10059 & 10080").Select
Columns("E:E").Select
Selection.TextToColumns Destination:=Range("E1"),
DataType:=xlDelimited, _
TextQualifier:=xlSingleQuote, ConsecutiveDelimiter:=False,
Tab:=True, _
Semicolon:=False, Comma:=False, Space:=False, Other:=False,
FieldInfo _
:=Array(1, 1), TrailingMinusNumbers:=True
Columns("G:G").Select
Selection.TextToColumns Destination:=Range("G1"),
DataType:=xlDelimited, _
TextQualifier:=xlSingleQuote, ConsecutiveDelimiter:=False,
Tab:=True, _
Semicolon:=False, Comma:=False, Space:=False, Other:=False,
FieldInfo _
:=Array(1, 1), TrailingMinusNumbers:=True
Range("A57").Select
End Sub- Hide quoted text -

- Show quoted text -

Thank you, this looks good and appears to be the correct solution, but
I am still getting a "object does not support this property or method"
error, highlighting the first lines of code.

If Sheets("All Other Funds Centers").CountA(Columns("E:E")) < 0 _
And Sheets("All Other Funds Centers").CountA(Columns("G:G")) _
< 0 Then- Hide quoted text -

- Show quoted text -

It took me awhile to get back to this, it is just what I needed,
Thanks.

One other question,
I have column in multiple worksheets of a workbook that are hidden.
I tried recording a macro to unhide the columns, but it error out each
time I try to run it. The columns are alway the same in the
worksheets, O-AR. Am I missing something.