Thread: Replace
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Per Jessen[_2_] Per Jessen[_2_] is offline
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Default Replace

HI

I assumed you had a date in the cell. As you have a month name in the
cell you can just use:

cMonth=Left(cells(13,4),3)
cYear=right(cells(13,5),2) ' Change cell reference to suit.

Hopes this helps.
....
Per

On 4 Aug., 21:05, Bishop wrote:
Ok thanks for the idea. *This is what I had to do to make it work:

* * Dim Month As Integer
* * If Cells(13, 4).Value = "January" Then Month = 1
* * If Cells(13, 4).Value = "February" Then Month = 2
* * If Cells(13, 4).Value = "March" Then Month = 3
* * If Cells(13, 4).Value = "April" Then Month = 4
* * If Cells(13, 4).Value = "May" Then Month = 5
* * If Cells(13, 4).Value = "June" Then Month = 6
* * If Cells(13, 4).Value = "July" Then Month = 7
* * If Cells(13, 4).Value = "August" Then Month = 8
* * If Cells(13, 4).Value = "September" Then Month = 9
* * If Cells(13, 4).Value = "October" Then Month = 10
* * If Cells(13, 4).Value = "November" Then Month = 11
* * If Cells(13, 4).Value = "December" Then Month = 12
* * CMonth = MonthName(Month, True)

But, I'm also trying to do the same thing with the year. *The cell value is
going to be 2009, 2010, 2011, etc. *I just need the last 2 digits. *How do I
accomplish that?



"Per Jessen" wrote:
Hi


Try this:


cMonth = MonthName(Month(Cells(13, 4)), True)


Regards,
Per


On 4 Aug., 20:34, Bishop wrote:
I have the following code:


CMonth = (Replace(Cells(13, 4).Value, "*", "???"))


The only value that will be in Cells(13, 4) will be one of the 12 months. *
What I'm trying to do is truncate the month to just the 1st 3 chars. *So if
the month is January, CMonth = Jan. *If it's October, CMonth = Oct. *So on
and so forth. *The way I have it set up it's not working as intended though. *
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