VarType(range-object)) returns the type info about the default property of
the object which is Value (though if a range had not yet been assigned to an
object variable then VarType will return vbObject 9).

If the range object refers to multiple cells Value returns a variant array,
irrespective of the cell contents, hence 8192 array + 12 variant = 8204

If the range refers to a single cell, VarType will return the type of the
individual value

I don't quite follow your points 2 & 3 but post back if the above does not
clarify what you are after.

Regards,
Peter T


"Neal Zimm" wrote in message
...
HI All,
I'm learning/testing with the vartype function and using variants in
called sub procs.

Code below is parts of larger macros. Sub Test2 processes TestVar
variable
depending on its type.

1. In sub Test1, why is vartype of a cell range 8204? Seems 'odd'. The
help shows 8192 for an array and 12 for vbVariant. Help is silent on why
a
cell range's vartype is not vbObject.

2. With more digging, I found the TypeName function.
Is: If "Range" = typename(TestVar) then .....

a 'good' way to check for a cell range object ?

3. Assuming an array is NOT a variant array containing different data
types in its elements, are the statements below roughly equivalent to test
for a numeric array ? (e.g. integer or long)
(Note: Coding efficiency not a consideration here)

Dim Name as string
Dim TestAy As Variant
'code establishing TestAy's element values

if isarray(TestAy) then if isnumeric(TestAy(1)) then .... '#1 assumes
base 1 option.

if "*()" like typename(TestAy) then '#2
name = typename(TestAy)
if instr("InteLong", left(name,4)) 0 then .....
end if

Thanks.
------------


sub Test1()
Dim TstRng As Range

Set TstRng = ActiveSheet.Range("p146:w146")
MsgBox VarType(TstRng), , "ActiveSheet.Range(p146:w146)" 'got 8204

call Test2(TstRng)
end sub



sub Test2(TestVar as variant)

if vartype(testvar) = vbstring then
'not shown code works when testvar is string

elseif vartype(testvar) = vbarray + vbinteger then
'not shown code works when testvar is integer array

elseif vartype(testvar) = vbobject then
'thought i'd get sub Test1's TstRng here, but did not.
'using TypeName(testvar) worked.
else
msgbox "Error vartype " & vartype(testvar) 'tested ok with "bad" input
end if
end sub
--
Neal Z