It worked when I put it in a new wb, but not when it's in my personal.xls wb.

"JLGWhiz" wrote:

Dave's function worked fine for me. I copied his code and pasted it in my
standard code module, then I put a thin solid border on a cell in cell A4.
Then in a cell in another column, I typed "ThinBottomBorder(a4)" without the
quote marks, pressed enter and a 1 appeared in that cell. Maybe, if you
explained how you tried his code the problem could be cleared up.

"Marco" wrote:

No go. Did as instructed and getting same error.

"Dave Peterson" wrote:

Put the entire code that I posted in its own module--Insert|Module--don't put it
in a worksheet module and don't put it under the ThisWorkbook module.


Marco wrote:

No go. Still getting the same error.

Do I need to put in "Option Explicit"?

"Dave Peterson" wrote:

You can use a UDF like:
Option Explicit
Function ThinBottomBorder(rng As Range) As Long
If rng.Cells(1).Borders(xlEdgeBottom).Weight = xlThin Then
ThinBottomBorder = 1
Else
ThinBottomBorder = 0
End If
End Function


Then put this in M15:
=thinbottomborder(a14)



Marco wrote:

I want to create a function that will check a cell for a bottom border and
return a 1 if True or 0 if False.

My function will be in cell M15, checking cell A14 for the border.

I have the following, which is returning a #NAME? error:

If Range.Select.Borders(xlEdgeBottom).Weight = xlThin _
Then ActiveCell.FormulaR1C1 = "1" Else ActiveCell.FomulaR1C1 = "0"

Thank you in advance for your help

Marco

--

Dave Peterson


--

Dave Peterson