How to extract "destination address" from Hyperlink - VBA
What I meant was "a check of the "komorka" variable shows that it is
equal to the value in cell A1, not a range reference to A1"
--JP
On Oct 23, 12:53*pm, JP wrote:
I duplicated your example, but was not able to duplicate the error.
The function exited immediately after hitting "If
komorka.Hyperlinks.Count = 0 Then " and a check of the 'komorka' shows
that it is equal to 100, not a range reference to A1.
--JP
On Oct 23, 12:13*pm, spwmarluk wrote:
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