Everything after this...

ActiveCell.FormulaR1C1 =

in your statement is a very long String value... you cannot do line
continuations in the middle of a String. For example, if you had this
line...

FakeLongLine = "This is supposed to be a long line"

you could NOT do this...

FakeLongLine = "This is supposed _
to be a long line"

which is what you did several times with your own long String value.
Instead, to do a line continuation on my example above, you would have to
form substrings, concatenate them and do the line continuation at the point
of concatenation....

FakeLongLine = "This is supposed" & _
"to be a long line"

Rick


"KarenF" wrote in message
...
Hello All -

I have an IF stmt that's fairly long, and it works.

Range("P2").Select
ActiveCell.FormulaR1C1 = "=IF(RC[-15]=""abc"",1.5,
IF(OR(RC[-1]={""xx"",""xx""}),4.0,
IF(OR(RC[-1]={""xx"",""xx"",""xx"",""xx"",""xx"",""xx"",""xx"" ,""xx""}),3.5,
IF(OR(RC[-1]={""xx"",""xx"",""xx"",""xx"",""xx"",""xx"",""xx"" ,""xx"",""xx""}),3,
IF(OR(RC[-1]={""A6"",""AB"",""AV"",""ZU"",""xx""}),2.5,
IF(OR(RC[-1]={""xx"",""xx"",""xx"",""xx"",""xx"",""xx"",""xx"" ,""xx"",""xx""}),2,
IF(OR(RC[-1]={""A1"",""A2"",""xx""}),1.5,"""")))))))"

However, if I try to break it into segments for useability, I get an
"Expected: end of statement" or "Syntax Error."

Range("P2").Select
ActiveCell.FormulaR1C1 = "=IF(RC[-15]=""abc"",1.5, _
IF(OR(RC[-1]={""xx"",""xx""}),4.0, _
IF(OR(RC[-1]={""xx"",""xx"",""xx"",""xx"",""xx"",""xx"",""xx"" ,""xx""}),3.5,
_
IF(OR(RC[-1]={""xx"",""xx"",""xx"",""xx"",""xx"",""xx"",""xx"" ,""xx"",""xx""}),3,
_
IF(OR(RC[-1]={""A6"",""AB"",""AV"",""ZU"",""xx""}),2.5, _
IF(OR(RC[-1]={""xx"",""xx"",""xx"",""xx"",""xx"",""xx"",""xx"" ,""xx"",""xx""}),2,
_
IF(OR(RC[-1]={""A1"",""A2"",""xx""}),1.5,"""")))))))"

The ONLY difference is the multiple lines. What is the magic to breaking
up
a line when I want more than 1 row?

KarenF