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Rick Rothstein \(MVP - VB\)[_2299_] Rick Rothstein \(MVP - VB\)[_2299_] is offline
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Default Extracting portion of filename

Assuming you have the filename in a String variable and that the filename
has an extension (assumed to be CSV for the following example, but the code
will work for any 3-character extension)...

Filename = "Daily 2008 07 12.csv"
TheDate = CDate(Replace(Mid(Filename, Len(Filename) - 13, 10), " ", "-"))

Rick


"HappySenior" wrote in message
...
I have a macro that creates a series of workbooks named in the format
"Daily yyyy mm dd" which works fine.
My daily worksheets require a column headed by the date and another
column headed by the preceding day's date. That column links to the
prior day's worksheet to bring forward end of the day values.
I'm a newbie (retired CPA) at VBA and would appreciate suggestions
about how to extract the right 10 characters of the file name and
convert them to a date in cell c1 on sheet 1.
Many thanks
Don