If the path and file exists then the code line is correct. Are you
assigning this to a object? If so use

Set wbkNew = Workbooks.Open ("G:\ReportFiles\ReportTemplate.xls")

--

Regards,
Nigel




"James8309" wrote in message
...
Hi everyone,

one of my line in my VBA code is ;

Workbooks.Open Filename:="G:\ReportFiles\ReportTemplate.xls"


and I do not understand why this line creates "Invalid Procedure call
or argument"

Please help

thank you,