On Jun 16, 6:05*pm, Karthi Ganesh
wrote:
Good work Mr.Bob, you found the mistake at the first attempt.
Thanks a lot.

regards
Karthi Ganesh



"Bob Phillips" wrote:
Sub Testing()

Dim LR As Integer
Dim LR1 As Integer
Dim Range123 As Range

LR = Range("A65000").End(xlUp).Row
LR1 = LR + 1

*Set Range123 = Sheets("Sheet1").Range("A2:A" & LR)
* * Range123.AdvancedFilter Action:=xlFilterCopy, _
* * * * * * * * * * * * * * CopyToRange:=Range("A" & LR1), _
* * * * * * * * * * * * * * Unique:=True

End Sub

--
---
HTH

Bob

(there's no email, no snail mail, but somewhere should be gmail in my addy)

"James8309" wrote in message
...
On Jun 16, 5:17 pm, Karthi Ganesh
wrote:
Did you check that there are sufficient rows below the last row of your
data?
It may be one reason.

"James8309" wrote:
On Jun 16, 4:50 pm, kg_singapore
wrote:
Where do you want the results to be placed,

one row below
or
one column right

In your code, you are trying place next row. Pl chk this

regards
KarthiGanesh

"James8309" wrote:
Hi,

I am trying to do an advance filter in VBA. I do not understand why
it
is creating a "reference error" I am just trying to paste the unique
advanced filter result to the very last row + 1 on column A. Can
anyone help? Thanks alot!

Sub Testing()

Dim LR as Integer
Dim LR1 as Integer
Dim Range123 as Range

LR = Range("A65000").End(xlUp).Row
LR1 = LR + 1

Set Range123 = Sheets("Sheet1").Range("A2:A" & LR)
Range123.AdvancedFilter Action:=xlFilterCopy, CopyToRange:=("A" &
LR1 _
), Unique:=True

End Sub

Regards

Jay- Hide quoted text -

- Show quoted text -

One row below the Last row. Why is it keep returning "Reference
error"?

Can you help?

Thx- Hide quoted text -

- Show quoted text -

Even if I do CopytoRange:=("C5") it returns the same error. column C:C
is totally empty.- Hide quoted text -

- Show quoted text -

omg, I am so dumb lol.

Thanks for your help guys! as always :D