Jip i choped and changed it a little bit when i saw the answer on my
spreadsheet. got one collum to show ur firs answer and made another colum
to show just the age of the person

thanx

pswanie
"Rick Rothstein (MVP - VB)" wrote in
message ...
Sorry, on your second question, I only gave you part of the formula. This
is what I should have posted...

=DATEDIF(DATE(LEFT(A1,2),MID(A1,3,2),MID(A1,5,2)), TODAY(),"y")

Rick


"Rick Rothstein (MVP - VB)" wrote in
message ...
For your first question, select the entire column, right click it and
choose Format Cells from the popup menu that appears, choose the Number
tab on the dialog box that appears, select Custom in the Category list
and copy/paste this in the Type field...

000000 0000 00 0

The answer for your second question is a little more problematic because
you are only using 2-digit years. Assuming no one will ever be more than
100 years old, try this formula...

=DATE(LEFT(A1,2),MID(A1,3,2),MID(A1,5,2))

where I have assumed your ID number is A1 (adjust the formula
accordingly).

Rick


"pswanie" wrote in message
...
Im from south africa. we use a ID number system. it looks and consist of
the
following

800506 5001 05 2
The user will enter the 13 numbers without space or any thing. What i
need is:

================================================== ==
colum d to automaticly put a space after the first 6 numbers and a space
after the next four numbers and then after the next to numbers ie:

8005065001052 = 800506 5001 05 2

then
colum e i need to deduct the first six numbers from todays date becouse
the
first six numbers represent the date of birth that is 1980-05-06

so colum e will then show the persons age ie: 28
================================================== ===

do appreciate

thanx
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