It depends on where the code is. If the code is behind a worksheet (not
pworksheet), then not qualifying it would cause trouble.


Bob Phillips wrote:

I don't think you have to qualify the Range, because the qualified Cells is
linking it to the worksheet, the Range is the Range object not the Range
property.

--
HTH

Bob

(there's no email, no snail mail, but somewhere should be gmail in my addy)

"Dave Peterson" wrote in message
...
I'd qualify all the range objects:

with pworksheet
set rHeader = .Range(.Cells(1, 1), .Cells(1, iColCount))
end with



Tim wrote:

Using VBA 6.5, I receive the runtime error when running
FormatQtrAnalysis.
I know it has to do something with the way I have set up the class
CSTIAnalysis.
Problem is I do not know what that something is.
Is there any suggestions as to what I am overlooking?
Any suggestions as to where to look at will be appreciated.
(Of course, an answer will Greatly Appreciated!)
From STIOptions Module

Sub FormatQtrAnalysis()
Dim csaQtrAnalysis As CSTIAnalysis
Set csaQtrAnalysis = New CSTIAnalysis
csaQtrAnalysis.Worksheet = ActiveSheet
csaQtrAnalysis.FormatHeader 'When pressing Debug, this line is
highlighted
End Sub

From CSTIAnalysis Class

Private pWorksheet As Worksheet

Public Property Get Worksheet() As Worksheet
Worksheet = pWorksheet
End Property
Public Property Let Worksheet(vNewValue As Worksheet)
Set pWorksheet = vNewValue
End Property

Public Sub FormatHeader()
Dim rHeader As Range
Dim iColCount As Integer
iColCount = pWorksheet.UsedRange.Columns.Count
rHeader = pWorksheet.Range(Cells(1, 1), Cells(1, iColCount))
rHeader.MergeCells = False
With rHeader
.Merge
.EntireRow.AutoFit
.BorderAround Weight:=xlThick, ColorIndex:=1
End With
End Sub

--

Dave Peterson

--

Dave Peterson