That's different than the code you posted yesterday when you were using ""

try this line

If rCell.Interior.ColorIndex = 35 And IsNull(rCell.Value) Then

Mike

"S Himmelrich" wrote:

I get a type mismatch

if I put this line I still get an object error

If rCell.Interior.ColorIndex = 35 And rCell.Value Is Null Then

Not sure what is going on...humm...



On Apr 9, 5:04 pm, Mike H wrote:
What error because there's nothing wrong with the code

Mike



"S Himmelrich" wrote:
I've been working on the following code, but get an error on the
designated line - can someone help?

Dim rCell As Range
Sheets("Form").Select
Range("B2:C450").Select
For Each rCell In Selection.Cells
If rCell.Interior.ColorIndex = 35 And rCell.Value = "" Then <---
ERROR OCCURS
rCell.Borders.Color = 3
End If
Next rCell- Hide quoted text -

- Show quoted text -