"Jarle" wrote in message
This works fine. Thank you!
I had to put in 0& as suggested by Peter T.
Unfortunatelely I still have a problem and a question:
1. If the document to open is an excel workbook. It seems that I reach an
infinite loop or something. The macro keeps running forever. Any Idea why?
How can I check if the document is an excel document. Then I can use the
application.open (?) command for such files.
If Right$(LCase$(sFile), 4) Like ".xl*" Then
Application.Workbooks.Open sFile
End If
first ought test to see if the file is already open
2. My excel version is 9.0. From which version will I need to use
application.hwnd?
It was introduced in v.10 XL2002
I would like my program to check version (application.version) and then
then
use the correct commandline.
It's probably OK simply to use 0& as I suggested, which defaults to the
desktop's window, but if you prefer following will work for all versions
Private Declare Function FindWindow Lib "user32" Alias "FindWindowA" ( _
ByVal lpClassName As String, ByVal lpWindowName As String) As Long
Dim XLhWin as Long
XLhWin = FindWindow("XLMAIN", Application.Caption)
Regards,
Peter T
PS, watch out for that "open", if vbNulllString works for you stick with
that
Jarle
Peter T skrev:
"Ivyleaf" wrote in message
...
On Apr 4, 8:06 pm, Jarle wrote:
Unfortunately is not that simple.
Folder1/folder2 is just an example. That path that I use is in the
program
is different, and I have checked that it is correct. Ehen I paste the
path+filename in the "Run" command in the Start menu (Windows), then
the
document opens.
I have also tried to leave out Chr(34) because is seems this gives "".
I have also made sure that I do not have space in pathname or
filename.
Still no solution.'
What I want to do is to open a file from VBA code. File might not be
office
document. Any suggestion?
Ivyleaf skrev:
On Apr 4, 6:38 pm, Jarle wrote:
I want to open a document. Document format may vary.
I try with:
Dim f_name as String
Dim Returnvalue as Variant
f_name ="E:\forlder1\folder2\test.pdf"
ReturnValue = Shell("start " & Chr$(34) & f_name Chr$(34) )
According to a tip on a different web-site this should open the
file
in the
program it is connected to (he Acrobat Reader).
I always get error message "file not found", but the file is
there.
What is wrong?
rgds
Jarle
Hi Jarle,
In your path, you have "Forlder1" which I reckon should maybe be
"Folder1"? This may be all that is wrong with your code.
Cheers,
Ivan.- Hide quoted text -
- Show quoted text -
Hi Jarle,
This doesn't use the Shell function, but it might do what you are
after:
Option Explicit
Private Declare Function ShellExecute Lib "shell32.dll" Alias
"ShellExecuteA" ( _
ByVal hwnd As Long, _
ByVal lpOperation As String, _
ByVal lpFile As String, _
Optional ByVal lpParameters As String, _
Optional ByVal lpDirectory As String, _
Optional ByVal nShowCmd As Long) As Long
Private Const SW_HIDE As Long = 0
Private Const SW_SHOWNORMAL As Long = 1
Private Const SW_SHOWMAXIMIZED As Long = 3
Private Const SW_SHOWMINIMIZED As Long = 2
Sub OpenFile()
Dim FName As String
Dim RetVal
FName = "E:\Folder 1\Folder 2\Test File.pdf"
ShellExecute Application.hwnd, "open", FName _
', vbNullString, "C:\", SW_SHOWNORMAL
End Sub
I found / pinched / adapted (slightly) the code from he
http://www.vbforums.com/showthread.php?t=481233
Cheers,
Ivan.
---------------------------------------------
ShellExecute Application.hwnd, "open", FName _
', vbNullString, "C:\", SW_SHOWNORMAL
For use in Excel 97 & 2000, change
Application.hwnd
to
0&
or use the FindWindow API to get the app's window handle
In later OS may need to change "open" to vbNullString
Regards,
Peter T