It eliminated the error message. However, the prices remain the same whether
or not cell $D$15 is "Affiliate" or not. If $D$15 reads "Affiliate", I need
cell $D$24's price to reduce by 50% of what it would normally be based on the
number of affiliates selected in cell $D$13. Thanks.
--
Cathy


"JE McGimpsey" wrote:

Hmm.. check your typing.

It's true that my copy/paste apparently left off the last closing paren
(so it should be:

=IF($E$24<=0,"",IF($D$13<1,"# of Vehicles MUST be 0",
LOOKUP($D$13, {1,500;26,750;51,1500;151,2000;251,5000})/(1 +
($D$15="Affiliate"))))

with four closing parens at the end), but there's nothing there that
should give a #NAME? error...

With

D13: 1
E24: 1

(i.e., no quotes), D24 returns 500.


In article ,
cathy wrote:

When using the formula suggested, I receive an error message (specifically
#NAME?) when I select cell $E$24 as "1" and cell $D$13 as "1" and $D$15 as
blank.
--
Cathy


"JE McGimpsey" wrote:

one way:

=IF($E$24<=0,"",IF($D$13<1,"# of Vehicles MUST be 0",
LOOKUP($D$13, {1,500; 26,750; 51,1500; 151,2000; 251,5000})/(1 +
($D$15="Affiliate")))