Define variable from cell to open a file
It works now. Needed ( ).
Workbooks.Open Filename:="V:\FTP Data\" & (strFileName)
"Amir" wrote:
Yes the file exists. I have strFilename1X.
"Jim Thomlinson" wrote:
Where does the 1X come from. By prefixing FileName with "str" we get aound
the reserved word issue.
Does a file exist such as
V:\FTP Data\Data-20070816.csv
--
HTH...
Jim Thomlinson
"Amir" wrote:
It errors out at the Filename:="V:\FTP Date\" & strFileName1X
"Jim Thomlinson" wrote:
Try this...
Dim strFileName as String
strFileName = Range("B1").Value
Workbooks.Open Filename:="V:\FTP Data\" & strFileName
Note - Don't declare a variable FileName as that is a reserved word(ish).
--
HTH...
Jim Thomlinson
"Amir" wrote:
I have it calling B1
"Amir" wrote:
I am trying to open a file that has a date in its name. EX Data-20070816.csv
I have the user input the date in one cell (a1) and have a string formula in
another cell (b1).
I keep getting an error when I try to define the variable.
Windows("Data Comparison.xls").Activate
Application.Run "BLPLinkReset"
Sheets("Sheet1").Select
Dim Filename As String
Set Filename = Range("B1").Select
Workbooks.Open Filename:="V:\FTP Data\(Filename)"
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