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Posted to microsoft.public.excel.programming
joel joel is offline
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Posts: 9,101
Default loop with do while

the staement below won't work because you arre dealing with strings

from
If ActiveCell < "89001/41" Then
to
if strcomp(ActiveCell,"89001/41") < 0 then


"Olamide" wrote:

below refuse to work. My objective is to search for 89001/43 in column A. if
my search enters run time error the if block will be executed. Inside the Do
block i want the 1st cell in column A that contain any value within the range
specified in the do block to be selected

Dim OtherBank As Variant
Const OBStart As Variant = "89000/41"
Const OBEnd As Variant = "89999/43"
Columns("A:A").Select ' Find Other Bank and Cash
On Error Resume Next
Selection.Find(What:="89001/41", After:=ActiveCell, LookIn:=xlFormulas, _
LookAt:=xlPart, SearchOrder:=xlByRows, SearchDirection:=xlNext, _
MatchCase:=False, SearchFormat:=False).Select
If ActiveCell < "89001/41" Then
OtherBank = Val(Selection.Value)
Range("A2").Select
Do While OtherBank < OBStart Or OtherBank OBEnd
Selection.Offset(1, 0).Select
OtherBank = Val(Selection.Value)
Loop
End If

Selection.EntireRow.Insert