thanks, to, i knew there was a way, just couldn't remember to use range.

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Gary


"Tom Ogilvy" wrote in message
...
? columns("K").Resize(,60).count
60


? Range(columns(11),columns(11+59)).count
60

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Regards,
Tom Ogilvy


"Gary Keramidas" <GKeramidasATmsn.com wrote in message
...
just curious:

is there a way to get the number of columns using column numbers instead of
letters?

columns("K:BR").count
returns 60

but i'd like to use the column numbers instead.

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Gary